TopCoder Problem Statement - Masterbrain

Simulate a classic board game with a slight twist.

001: /* 002: TopCoder 003: Single Round Match: 146 004: Division: 1 005: Level: 2 006: Points: 600 007: Description: http://community.topcoder.com/stat?c=problem_statement&pm=1541 008: */ 009: 010: public class Masterbrain { 011: 012: /* 013: A good solution is one in which all the results match the corresponding 014: guesses - except for 1. 015: Loop through each of the guess/result pairs for the solution checking to 016: see if one, and only one, does not match up. 017: */ 018: private static boolean goodSolution(String solution, String[] guesses, 019: String[] results) { 020: 021: boolean lied = false; 022: 023: for (int i = 0; i < guesses.length; i++) { 024: 025: // Always a single digit, and always in the same spot. 026: int numBlack = Integer.parseInt("" + results[i].charAt(0)); 027: int numWhite = Integer.parseInt("" + results[i].charAt(3)); 028: 029: if (!resultMatches(guesses[i], solution, numBlack, numWhite)) { 030: if (lied) { 031: return false; // That's two lies - return false. 032: } else { 033: lied = true; // First lie. 034: } 035: } 036: } 037: 038: return lied; 039: } 040: 041: /* 042: Compares the guess with the solutions, and returns whether or not the 043: number of black and white pegs matches up. 044: */ 045: private static boolean resultMatches(String guess, String solution, 046: int numBlack, int numWhite) { 047: 048: // Used to keep tracks of which pegs have already been assigned. 049: boolean[] usedBlack = new boolean[guess.length()]; 050: boolean[] usedWhite = new boolean[guess.length()]; 051: 052: // Check if numBlack matches 053: int numInCorrectPosition = 0; 054: 055: for (int i = 0; i < guess.length(); i++) { 056: if (guess.charAt(i) == solution.charAt(i)) { 057: numInCorrectPosition++; 058: usedBlack[i] = true; 059: } 060: } 061: 062: // If numBlack does not match, no point in checking the white pegs. 063: if (numInCorrectPosition != numBlack) { 064: return false; 065: } 066: 067: // Check if numWhite matches 068: int numOutOfPositon = 0; 069: for (int i = 0; i < guess.length(); i++) { 070: 071: /* 072: If we're looking at a position that has already been assigned a 073: black peg, then continue. 074: */ 075: if (usedBlack[i]) { 076: continue; 077: } 078: 079: for (int j = 0; j < guess.length(); j++) { 080: 081: // Again, skip over assigned pegs. 082: if (usedBlack[j]) { 083: continue; 084: } 085: 086: if ((guess.charAt(i) == solution.charAt(j)) && !usedWhite[j]) { 087: numOutOfPositon++; 088: usedWhite[j] = true; 089: break; // Skip to next i, not j. 090: } 091: } 092: } 093: 094: return numOutOfPositon == numWhite; 095: } 096: 097: public int possibleSecrets(String[] guesses, String[] results) { 098: 099: int count = 0; 100: 101: /* 102: Generate all possible solutions. For each solution, 103: if it meets the criteria of a good solution, then increment count. 104: When done, return count. 105: */ 106: for (char h = '1'; h < '8'; h++) { 107: for (char i = '1'; i < '8'; i++) { 108: for (char j = '1'; j < '8'; j++) { 109: for (char k = '1'; k < '8'; k++) { 110: String solution = "" + h + i + j + k; 111: if (goodSolution(solution, guesses, results)) { 112: count++; 113: } 114: } 115: } 116: } 117: } 118: 119: return count; 120: } 121: }

possibleSecrets() generates all possible secret codes. There's only 7 * 7 * 7 * 7 = 2,401 of them, so it's not that many. For each of the possible code, it calls goodSolution() to see if the solution, guesses, and results agree. If so, the count is increased. When done, count will contain the number of solutions that satisfy the game's criteria.

goodSolution() loops through all the guess/response pairs for the given solution, and determines if they satisfy the rules of the game. That is, one, and only one, result does not agree with the given guess and solution. You might think that being able to lie once would make the game much more difficult, but it doesn't. Initially, lied is set to false. The first time a response doesn't match the guess, lied gets set to true. If it happens again, then return false - this cannot be a good solution, since there were two mis-matches. When done, return lied, which will be true if one was found, and false if not.

The most difficult part of the problem is determining if the response matches the guess for the given solution. This is handled in resultMatches(). First, it checks if the number of black pegs matches the number of items in guess that in their correct position. Then, it looks for items that match, but are out of place. Just be careful here to avoid double-counting. The usedBlack[] and usedWhite[] arrays are for keeping track of pegs that have already been accounted for.

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